Newton's method to Solutions f(x) = x3 - x -1 with xn = 1
n xn f(xn) f\(xn) xn+1 Drive6
0 1 -1 2 1.5 SOLVE(x3  - x - 1, x, Real)
1 1.5 0.875 5.75 1.347826087 Back x = 1.324717957
2 1.347826087 0.100682173 4.449905482 1.325200399
3 1.325200399 0.002058362 4.268468292 1.324718174
4 1.324718174 9.24378E-07 4.264634722 1.324717957
5 1.324717957 1.86517E-13 4.264632999 1.324717957
6 1.324717957 0 4.264632999 1.324717957